(3/2)x+x^2-22=0

Solution for (3/2)x+x^2-22=0 equation:

(3/2)x+x^2-22=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x^2+(+3/2)x-22=0

We multiply parentheses

x^2+3x^2-22=0

We add all the numbers together, and all the variables

4x^2-22=0

a = 4; b = 0; c = -22;
Δ = b2-4ac
Δ = 02-4·4·(-22)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{22}}{2*4}=\frac{0-4\sqrt{22}}{8}
=-\frac{4\sqrt{22}}{8}
=-\frac{\sqrt{22}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{22}}{2*4}=\frac{0+4\sqrt{22}}{8}
=\frac{4\sqrt{22}}{8}
=\frac{\sqrt{22}}{2}
$